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Help me get an answer for ײ-8x+41

asked Aug 22, 2017 in Algebra by Tailor

1 Answer

x^2-8x+41=0

x^2-8x      =-41

(8/2)^2=4^2=16

x^2-8x+16=-41+16

(x-4)^2=-25

x-4=+sqrt(-25)

x-4=+5i

x=4+5i

x=4+5i and x=4-5i
answered Aug 22, 2017 by quickwriter (2,510 points)
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