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Help me get an answer for ×²-8x+41
asked
Aug 22, 2017
in
Algebra
by
Tailor
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1 Answer
x^2-8x+41=0
x^2-8x =-41
(8/2)^2=4^2=16
x^2-8x+16=-41+16
(x-4)^2=-25
x-4=+sqrt(-25)
x-4=+5i
x=4+5i
x=4+5i and x=4-5i
answered
Aug 22, 2017
by
quickwriter
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2,510
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