Home
About
Prices
Testimonials
Contacts
Assignment help
My Account
Questions
Unanswered
Tags
Ask a Question
Welcome to Questions & Answers on Math, Physics, Chemistry, History and more, where you can ask questions and receive answers from other members of the community.
All categories
Chemistry
(37)
Math
(108)
Algebra
(108)
Physics
(17)
Programming
(5)
equilibrium equation A + B = C
There is given the equilibrium constant k = [A][B]/[C]
find the value of constant K
There is given information:
3C=D (Kc=7.9*10^-4)
D=3A+3B (Kc= 6.7*10^-2)
asked
Aug 18, 2017
in
Algebra
by
Rayan
Please
log in
or
register
to answer this question.
1 Answer
Solving the problem can be a little bit tricky, so you can try this way:
3C = D k1 = [D]/[C]^3 = 7.9*10^-4
D = 3A + 3B k2 = [A] ^3/[B]^3 = 6.7*10^-2
k1 x k2 = [A]^3 [B]^3 / [C]^3 = {[A][B]/[C]} ^3
answered
Aug 21, 2017
by
quickwriter
(
2,510
points)
Please
log in
or
register
to add a comment.
...