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Find (4sin2x-1)sinx=0 for the interval [0,2pi)
asked
Aug 18, 2017
in
Algebra
by
Kile
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1 Answer
Hey1
it's given that sin^2x = 1/4
sin x = 1/2, x = pi/6, 5pi/6
also
sin x = -1/2, x = 7pi/6, 11pi/6
So the answer is
x = pi/6, 5pi, 7pi.6, 11pi/6.
answered
Aug 21, 2017
by
quickwriter
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2,510
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