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Calculate enthalpy change

Need to calculate endalpy change for C2H4(g) + H2O(g)CH3CH2OH(g)
asked Aug 17, 2017 in Chemistry by Katrin

1 Answer

C2H4(g) + H2O(g) ===> CH3CH2OH(g)

∆Hrxn = -201 - (52.3 + -242) = -201 - (-189.7)

∆Hrxn = -11.3 KJ/mole

answered Aug 21, 2017 by quickwriter (2,510 points)
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